# Line slope calculator 3x+8y=32

**Straight line given by points A[0; 4] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.375x+4

**Canonical form of the line equation:**3x+8y-32 = 0

**Parametric form of the line equation:**

x = 8t

y = -3t+4 ; t ∈ R

**Slope:**m = -0.375

**Slope angle of line: φ =**-20°33'22″ = -0.3588 rad

**X intercept:**x

_{0}= 10.6667

**Y intercept:**y

_{0}= q = 4

**Distance line from the origin:**d

_{0}= 3.7453

**The length of the segment AB: |AB| =**8.544

**Vector: AB =**(8; -3)

**Normal vector: n =**(3; 8)

**Midpoint of the segment AB: M =**[4; 2.5]

**Perpendicular Bisector equation:**8x-3y-24.5 = 0

**Vector OA = (0; 4) ; |OA| = 4**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 4**

**Angle ∠ AOB = 82°52'30″ = 1.4464 rad**